3(y+4)=1+4y

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Solution for 3(y+4)=1+4y equation: 



3(y+4)=1+4y

We move all terms to the left:

3(y+4)-(1+4y)=0

We add all the numbers together, and all the variables

3(y+4)-(4y+1)=0

We multiply parentheses

3y-(4y+1)+12=0

We get rid of parentheses

3y-4y-1+12=0

We add all the numbers together, and all the variables

-1y+11=0

We move all terms containing y to the left, all other terms to the right

-y=-11

y=-11/-1

y=+11

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