3(y+4)=3(y-2)

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Solution for 3(y+4)=3(y-2) equation: 


Simplifying
3(y + 4) = 3(y + -2)

Reorder the terms:
3(4 + y) = 3(y + -2)
(4 * 3 + y * 3) = 3(y + -2)
(12 + 3y) = 3(y + -2)

Reorder the terms:
12 + 3y = 3(-2 + y)
12 + 3y = (-2 * 3 + y * 3)
12 + 3y = (-6 + 3y)

Add '-3y' to each side of the equation.
12 + 3y + -3y = -6 + 3y + -3y

Combine like terms: 3y + -3y = 0
12 + 0 = -6 + 3y + -3y
12 = -6 + 3y + -3y

Combine like terms: 3y + -3y = 0
12 = -6 + 0
12 = -6

Solving
12 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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