3(y+4)=35

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Solution for 3(y+4)=35 equation: 



3(y+4)=35

We move all terms to the left:

3(y+4)-(35)=0

We multiply parentheses

3y+12-35=0

We add all the numbers together, and all the variables

3y-23=0

We move all terms containing y to the left, all other terms to the right

3y=23

y=23/3

y=7+2/3

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