3(y+4)=5(7+2)

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Solution for 3(y+4)=5(7+2) equation: 



3(y+4)=5(7+2)

We move all terms to the left:

3(y+4)-(5(7+2))=0

We add all the numbers together, and all the variables

3(y+4)-(59)=0

We add all the numbers together, and all the variables

3(y+4)-59=0

We multiply parentheses

3y+12-59=0

We add all the numbers together, and all the variables

3y-47=0

We move all terms containing y to the left, all other terms to the right

3y=47

y=47/3

y=15+2/3

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