3(y+4)=60-y

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Solution for 3(y+4)=60-y equation: 



3(y+4)=60-y

We move all terms to the left:

3(y+4)-(60-y)=0

We add all the numbers together, and all the variables

3(y+4)-(-1y+60)=0

We multiply parentheses

3y-(-1y+60)+12=0

We get rid of parentheses

3y+1y-60+12=0

We add all the numbers together, and all the variables

4y-48=0

We move all terms containing y to the left, all other terms to the right

4y=48

y=48/4

y=12

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