3(y+4)=6y+36

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Solution for 3(y+4)=6y+36 equation: 



3(y+4)=6y+36

We move all terms to the left:

3(y+4)-(6y+36)=0

We multiply parentheses

3y-(6y+36)+12=0

We get rid of parentheses

3y-6y-36+12=0

We add all the numbers together, and all the variables

-3y-24=0

We move all terms containing y to the left, all other terms to the right

-3y=24

y=24/-3

y=-8

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