3(y+4)=7(3-y)

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Solution for 3(y+4)=7(3-y) equation: 



3(y+4)=7(3-y)

We move all terms to the left:

3(y+4)-(7(3-y))=0

We add all the numbers together, and all the variables

3(y+4)-(7(-1y+3))=0

We multiply parentheses

3y-(7(-1y+3))+12=0



We calculate terms in parentheses: -(7(-1y+3)), so:

7(-1y+3)

We multiply parentheses

-7y+21

Back to the equation:

-(-7y+21)



We get rid of parentheses

3y+7y-21+12=0

We add all the numbers together, and all the variables

10y-9=0

We move all terms containing y to the left, all other terms to the right

10y=9

y=9/10

y=9/10

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