3(y+4)=8y-1

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Solution for 3(y+4)=8y-1 equation: 



3(y+4)=8y-1

We move all terms to the left:

3(y+4)-(8y-1)=0

We multiply parentheses

3y-(8y-1)+12=0

We get rid of parentheses

3y-8y+1+12=0

We add all the numbers together, and all the variables

-5y+13=0

We move all terms containing y to the left, all other terms to the right

-5y=-13

y=-13/-5

y=2+3/5

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