3(y+4)=y+1+2y

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Solution for 3(y+4)=y+1+2y equation:


Simplifying
3(y + 4) = y + 1 + 2y

Reorder the terms:
3(4 + y) = y + 1 + 2y
(4 * 3 + y * 3) = y + 1 + 2y
(12 + 3y) = y + 1 + 2y

Reorder the terms:
12 + 3y = 1 + y + 2y

Combine like terms: y + 2y = 3y
12 + 3y = 1 + 3y

Add '-3y' to each side of the equation.
12 + 3y + -3y = 1 + 3y + -3y

Combine like terms: 3y + -3y = 0
12 + 0 = 1 + 3y + -3y
12 = 1 + 3y + -3y

Combine like terms: 3y + -3y = 0
12 = 1 + 0
12 = 1

Solving
12 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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