3(y+41)=3y+1233(y+41)=3y+123

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Solution for 3(y+41)=3y+1233(y+41)=3y+123 equation: 



3(y+41)=3y+1233(y+41)=3y+123

We move all terms to the left:

3(y+41)-(3y+1233(y+41))=0

We multiply parentheses

3y-(3y+1233(y+41))+123=0



We calculate terms in parentheses: -(3y+1233(y+41)), so:

3y+1233(y+41)

We multiply parentheses

3y+1233y+50553

We add all the numbers together, and all the variables

1236y+50553

Back to the equation:

-(1236y+50553)



We get rid of parentheses

3y-1236y-50553+123=0

We add all the numbers together, and all the variables

-1233y-50430=0

We move all terms containing y to the left, all other terms to the right

-1233y=50430

y=50430/-1233

y=-40+370/411

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