3(y+5)+10(y-4)+5=y

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Solution for 3(y+5)+10(y-4)+5=y equation: 



3(y+5)+10(y-4)+5=y

We move all terms to the left:

3(y+5)+10(y-4)+5-(y)=0

We add all the numbers together, and all the variables

-1y+3(y+5)+10(y-4)+5=0

We multiply parentheses

-1y+3y+10y+15-40+5=0

We add all the numbers together, and all the variables

12y-20=0

We move all terms containing y to the left, all other terms to the right

12y=20

y=20/12

y=1+2/3

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