3(y+5)-2(y-19)=12

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Solution for 3(y+5)-2(y-19)=12 equation: 



3(y+5)-2(y-19)=12

We move all terms to the left:

3(y+5)-2(y-19)-(12)=0

We multiply parentheses

3y-2y+15+38-12=0

We add all the numbers together, and all the variables

y+41=0

We move all terms containing y to the left, all other terms to the right

y=-41

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