3(y+5)=-3(4y-4)+3y

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Solution for 3(y+5)=-3(4y-4)+3y equation: 



3(y+5)=-3(4y-4)+3y

We move all terms to the left:

3(y+5)-(-3(4y-4)+3y)=0

We multiply parentheses

3y-(-3(4y-4)+3y)+15=0



We calculate terms in parentheses: -(-3(4y-4)+3y), so:

-3(4y-4)+3y

We add all the numbers together, and all the variables

3y-3(4y-4)

We multiply parentheses

3y-12y+12

We add all the numbers together, and all the variables

-9y+12

Back to the equation:

-(-9y+12)



We get rid of parentheses

3y+9y-12+15=0

We add all the numbers together, and all the variables

12y+3=0

We move all terms containing y to the left, all other terms to the right

12y=-3

y=-3/12

y=-1/4

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