3(y+5)=-3(6y-6)+9y

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Solution for 3(y+5)=-3(6y-6)+9y equation: 



3(y+5)=-3(6y-6)+9y

We move all terms to the left:

3(y+5)-(-3(6y-6)+9y)=0

We multiply parentheses

3y-(-3(6y-6)+9y)+15=0



We calculate terms in parentheses: -(-3(6y-6)+9y), so:

-3(6y-6)+9y

We add all the numbers together, and all the variables

9y-3(6y-6)

We multiply parentheses

9y-18y+18

We add all the numbers together, and all the variables

-9y+18

Back to the equation:

-(-9y+18)



We get rid of parentheses

3y+9y-18+15=0

We add all the numbers together, and all the variables

12y-3=0

We move all terms containing y to the left, all other terms to the right

12y=3

y=3/12

y=1/4

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