3(y+5)=-6(3y-2)+6y

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Solution for 3(y+5)=-6(3y-2)+6y equation: 



3(y+5)=-6(3y-2)+6y

We move all terms to the left:

3(y+5)-(-6(3y-2)+6y)=0

We multiply parentheses

3y-(-6(3y-2)+6y)+15=0



We calculate terms in parentheses: -(-6(3y-2)+6y), so:

-6(3y-2)+6y

We add all the numbers together, and all the variables

6y-6(3y-2)

We multiply parentheses

6y-18y+12

We add all the numbers together, and all the variables

-12y+12

Back to the equation:

-(-12y+12)



We get rid of parentheses

3y+12y-12+15=0

We add all the numbers together, and all the variables

15y+3=0

We move all terms containing y to the left, all other terms to the right

15y=-3

y=-3/15

y=-1/5

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