3(y+5)=2y+15+yB

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Solution for 3(y+5)=2y+15+yB equation: 



3(y+5)=2y+15+y

We move all terms to the left:

3(y+5)-(2y+15+y)=0

We add all the numbers together, and all the variables

3(y+5)-(3y+15)=0

We multiply parentheses

3y-(3y+15)+15=0

We get rid of parentheses

3y-3y-15+15=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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