3(y+6)+5=6(3y-2)

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Solution for 3(y+6)+5=6(3y-2) equation: 



3(y+6)+5=6(3y-2)

We move all terms to the left:

3(y+6)+5-(6(3y-2))=0

We multiply parentheses

3y-(6(3y-2))+18+5=0



We calculate terms in parentheses: -(6(3y-2)), so:

6(3y-2)

We multiply parentheses

18y-12

Back to the equation:

-(18y-12)



We add all the numbers together, and all the variables

3y-(18y-12)+23=0

We get rid of parentheses

3y-18y+12+23=0

We add all the numbers together, and all the variables

-15y+35=0

We move all terms containing y to the left, all other terms to the right

-15y=-35

y=-35/-15

y=2+1/3

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