3(y+6)=-2(8y-6)+y

Solution for 3(y+6)=-2(8y-6)+y equation:

3(y+6)=-2(8y-6)+y

We move all terms to the left:

3(y+6)-(-2(8y-6)+y)=0

We multiply parentheses

3y-(-2(8y-6)+y)+18=0


We calculate terms in parentheses: -(-2(8y-6)+y), so:

-2(8y-6)+y

We add all the numbers together, and all the variables

y-2(8y-6)

We multiply parentheses

y-16y+12

We add all the numbers together, and all the variables

-15y+12

Back to the equation:

-(-15y+12)


We get rid of parentheses

3y+15y-12+18=0

We add all the numbers together, and all the variables

18y+6=0

We move all terms containing y to the left, all other terms to the right

18y=-6

y=-6/18

y=-1/3