3(y+6)=-2(8y-7)+3y

Solution for 3(y+6)=-2(8y-7)+3y equation:

3(y+6)=-2(8y-7)+3y

We move all terms to the left:

3(y+6)-(-2(8y-7)+3y)=0

We multiply parentheses

3y-(-2(8y-7)+3y)+18=0


We calculate terms in parentheses: -(-2(8y-7)+3y), so:

-2(8y-7)+3y

We add all the numbers together, and all the variables

3y-2(8y-7)

We multiply parentheses

3y-16y+14

We add all the numbers together, and all the variables

-13y+14

Back to the equation:

-(-13y+14)


We get rid of parentheses

3y+13y-14+18=0

We add all the numbers together, and all the variables

16y+4=0

We move all terms containing y to the left, all other terms to the right

16y=-4

y=-4/16

y=-1/4