3(y+8)+y=2(y+2)-8

Solution for 3(y+8)+y=2(y+2)-8 equation:

3(y+8)+y=2(y+2)-8

We move all terms to the left:

3(y+8)+y-(2(y+2)-8)=0

We add all the numbers together, and all the variables

y+3(y+8)-(2(y+2)-8)=0

We multiply parentheses

y+3y-(2(y+2)-8)+24=0


We calculate terms in parentheses: -(2(y+2)-8), so:

2(y+2)-8

We multiply parentheses

2y+4-8

We add all the numbers together, and all the variables

2y-4

Back to the equation:

-(2y-4)


We add all the numbers together, and all the variables

4y-(2y-4)+24=0

We get rid of parentheses

4y-2y+4+24=0

We add all the numbers together, and all the variables

2y+28=0

We move all terms containing y to the left, all other terms to the right

2y=-28

y=-28/2

y=-14