3(y+8)=-2(4y-5)+7y

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Solution for 3(y+8)=-2(4y-5)+7y equation: 



3(y+8)=-2(4y-5)+7y

We move all terms to the left:

3(y+8)-(-2(4y-5)+7y)=0

We multiply parentheses

3y-(-2(4y-5)+7y)+24=0



We calculate terms in parentheses: -(-2(4y-5)+7y), so:

-2(4y-5)+7y

We add all the numbers together, and all the variables

7y-2(4y-5)

We multiply parentheses

7y-8y+10

We add all the numbers together, and all the variables

-1y+10

Back to the equation:

-(-1y+10)



We get rid of parentheses

3y+1y-10+24=0

We add all the numbers together, and all the variables

4y+14=0

We move all terms containing y to the left, all other terms to the right

4y=-14

y=-14/4

y=-3+1/2

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