3(y+8)=-3(3y-5)+6y

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Solution for 3(y+8)=-3(3y-5)+6y equation: 



3(y+8)=-3(3y-5)+6y

We move all terms to the left:

3(y+8)-(-3(3y-5)+6y)=0

We multiply parentheses

3y-(-3(3y-5)+6y)+24=0



We calculate terms in parentheses: -(-3(3y-5)+6y), so:

-3(3y-5)+6y

We add all the numbers together, and all the variables

6y-3(3y-5)

We multiply parentheses

6y-9y+15

We add all the numbers together, and all the variables

-3y+15

Back to the equation:

-(-3y+15)



We get rid of parentheses

3y+3y-15+24=0

We add all the numbers together, and all the variables

6y+9=0

We move all terms containing y to the left, all other terms to the right

6y=-9

y=-9/6

y=-1+1/2

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