3(y+8)=-3(3y-6)+8y

Solution for 3(y+8)=-3(3y-6)+8y equation:

3(y+8)=-3(3y-6)+8y

We move all terms to the left:

3(y+8)-(-3(3y-6)+8y)=0

We multiply parentheses

3y-(-3(3y-6)+8y)+24=0


We calculate terms in parentheses: -(-3(3y-6)+8y), so:

-3(3y-6)+8y

We add all the numbers together, and all the variables

8y-3(3y-6)

We multiply parentheses

8y-9y+18

We add all the numbers together, and all the variables

-1y+18

Back to the equation:

-(-1y+18)


We get rid of parentheses

3y+1y-18+24=0

We add all the numbers together, and all the variables

4y+6=0

We move all terms containing y to the left, all other terms to the right

4y=-6

y=-6/4

y=-1+1/2