3(y-1)+(y+3)=13

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Solution for 3(y-1)+(y+3)=13 equation: 



3(y-1)+(y+3)=13

We move all terms to the left:

3(y-1)+(y+3)-(13)=0

We multiply parentheses

3y+(y+3)-3-13=0

We get rid of parentheses

3y+y+3-3-13=0

We add all the numbers together, and all the variables

4y-13=0

We move all terms containing y to the left, all other terms to the right

4y=13

y=13/4

y=3+1/4

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