3(y-1)+13=8y+10-5y

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Solution for 3(y-1)+13=8y+10-5y equation: 


Simplifying
3(y + -1) + 13 = 8y + 10 + -5y

Reorder the terms:
3(-1 + y) + 13 = 8y + 10 + -5y
(-1 * 3 + y * 3) + 13 = 8y + 10 + -5y
(-3 + 3y) + 13 = 8y + 10 + -5y

Reorder the terms:
-3 + 13 + 3y = 8y + 10 + -5y

Combine like terms: -3 + 13 = 10
10 + 3y = 8y + 10 + -5y

Reorder the terms:
10 + 3y = 10 + 8y + -5y

Combine like terms: 8y + -5y = 3y
10 + 3y = 10 + 3y

Add '-10' to each side of the equation.
10 + -10 + 3y = 10 + -10 + 3y

Combine like terms: 10 + -10 = 0
0 + 3y = 10 + -10 + 3y
3y = 10 + -10 + 3y

Combine like terms: 10 + -10 = 0
3y = 0 + 3y
3y = 3y

Add '-3y' to each side of the equation.
3y + -3y = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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