3(y-1)+2(y+3)=-13

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Solution for 3(y-1)+2(y+3)=-13 equation: 



3(y-1)+2(y+3)=-13

We move all terms to the left:

3(y-1)+2(y+3)-(-13)=0

We add all the numbers together, and all the variables

3(y-1)+2(y+3)+13=0

We multiply parentheses

3y+2y-3+6+13=0

We add all the numbers together, and all the variables

5y+16=0

We move all terms containing y to the left, all other terms to the right

5y=-16

y=-16/5

y=-3+1/5

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