3(y-1)+2(y+3)=13

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Solution for 3(y-1)+2(y+3)=13 equation:


Simplifying
3(y + -1) + 2(y + 3) = 13

Reorder the terms:
3(-1 + y) + 2(y + 3) = 13
(-1 * 3 + y * 3) + 2(y + 3) = 13
(-3 + 3y) + 2(y + 3) = 13

Reorder the terms:
-3 + 3y + 2(3 + y) = 13
-3 + 3y + (3 * 2 + y * 2) = 13
-3 + 3y + (6 + 2y) = 13

Reorder the terms:
-3 + 6 + 3y + 2y = 13

Combine like terms: -3 + 6 = 3
3 + 3y + 2y = 13

Combine like terms: 3y + 2y = 5y
3 + 5y = 13

Solving
3 + 5y = 13

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 5y = 13 + -3

Combine like terms: 3 + -3 = 0
0 + 5y = 13 + -3
5y = 13 + -3

Combine like terms: 13 + -3 = 10
5y = 10

Divide each side by '5'.
y = 2

Simplifying
y = 2

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