3(y-1)+2(y+6)=13

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Solution for 3(y-1)+2(y+6)=13 equation: 



3(y-1)+2(y+6)=13

We move all terms to the left:

3(y-1)+2(y+6)-(13)=0

We multiply parentheses

3y+2y-3+12-13=0

We add all the numbers together, and all the variables

5y-4=0

We move all terms containing y to the left, all other terms to the right

5y=4

y=4/5

y=4/5

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