3(y-1)+7=4y+2-3(2-y)

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Solution for 3(y-1)+7=4y+2-3(2-y) equation: 



3(y-1)+7=4y+2-3(2-y)

We move all terms to the left:

3(y-1)+7-(4y+2-3(2-y))=0

We add all the numbers together, and all the variables

3(y-1)-(4y+2-3(-1y+2))+7=0

We multiply parentheses

3y-(4y+2-3(-1y+2))-3+7=0



We calculate terms in parentheses: -(4y+2-3(-1y+2)), so:

4y+2-3(-1y+2)

determiningTheFunctionDomain
4y-3(-1y+2)+2

We multiply parentheses

4y+3y-6+2

We add all the numbers together, and all the variables

7y-4

Back to the equation:

-(7y-4)



We add all the numbers together, and all the variables

3y-(7y-4)+4=0

We get rid of parentheses

3y-7y+4+4=0

We add all the numbers together, and all the variables

-4y+8=0

We move all terms containing y to the left, all other terms to the right

-4y=-8

y=-8/-4

y=+2

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