3(y-1)-(3y-1)=2y-1-(2y+1)

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Solution for 3(y-1)-(3y-1)=2y-1-(2y+1) equation:


Simplifying
3(y + -1) + -1(3y + -1) = 2y + -1 + -1(2y + 1)

Reorder the terms:
3(-1 + y) + -1(3y + -1) = 2y + -1 + -1(2y + 1)
(-1 * 3 + y * 3) + -1(3y + -1) = 2y + -1 + -1(2y + 1)
(-3 + 3y) + -1(3y + -1) = 2y + -1 + -1(2y + 1)

Reorder the terms:
-3 + 3y + -1(-1 + 3y) = 2y + -1 + -1(2y + 1)
-3 + 3y + (-1 * -1 + 3y * -1) = 2y + -1 + -1(2y + 1)
-3 + 3y + (1 + -3y) = 2y + -1 + -1(2y + 1)

Reorder the terms:
-3 + 1 + 3y + -3y = 2y + -1 + -1(2y + 1)

Combine like terms: -3 + 1 = -2
-2 + 3y + -3y = 2y + -1 + -1(2y + 1)

Combine like terms: 3y + -3y = 0
-2 + 0 = 2y + -1 + -1(2y + 1)
-2 = 2y + -1 + -1(2y + 1)

Reorder the terms:
-2 = 2y + -1 + -1(1 + 2y)
-2 = 2y + -1 + (1 * -1 + 2y * -1)
-2 = 2y + -1 + (-1 + -2y)

Reorder the terms:
-2 = -1 + -1 + 2y + -2y

Combine like terms: -1 + -1 = -2
-2 = -2 + 2y + -2y

Combine like terms: 2y + -2y = 0
-2 = -2 + 0
-2 = -2

Add '2' to each side of the equation.
-2 + 2 = -2 + 2

Combine like terms: -2 + 2 = 0
0 = -2 + 2

Combine like terms: -2 + 2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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