3(y-1)-3(3y+4)=2

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Solution for 3(y-1)-3(3y+4)=2 equation: 



3(y-1)-3(3y+4)=2

We move all terms to the left:

3(y-1)-3(3y+4)-(2)=0

We multiply parentheses

3y-9y-3-12-2=0

We add all the numbers together, and all the variables

-6y-17=0

We move all terms containing y to the left, all other terms to the right

-6y=17

y=17/-6

y=-2+5/6

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