3(y-1)=2(9+y)

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Solution for 3(y-1)=2(9+y) equation:



3(y-1)=2(9+y)
We move all terms to the left:
3(y-1)-(2(9+y))=0
We add all the numbers together, and all the variables
3(y-1)-(2(y+9))=0
We multiply parentheses
3y-(2(y+9))-3=0
We calculate terms in parentheses: -(2(y+9)), so:
2(y+9)
We multiply parentheses
2y+18
Back to the equation:
-(2y+18)
We get rid of parentheses
3y-2y-18-3=0
We add all the numbers together, and all the variables
y-21=0
We move all terms containing y to the left, all other terms to the right
y=21

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