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3(y-1)=2(y+1)
We move all terms to the left:
3(y-1)-(2(y+1))=0
We multiply parentheses
3y-(2(y+1))-3=0
We calculate terms in parentheses: -(2(y+1)), so:We get rid of parentheses
2(y+1)
We multiply parentheses
2y+2
Back to the equation:
-(2y+2)
3y-2y-2-3=0
We add all the numbers together, and all the variables
y-5=0
We move all terms containing y to the left, all other terms to the right
y=5
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