3(y-1)=2y+4

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Solution for 3(y-1)=2y+4 equation: 



3(y-1)=2y+4

We move all terms to the left:

3(y-1)-(2y+4)=0

We multiply parentheses

3y-(2y+4)-3=0

We get rid of parentheses

3y-2y-4-3=0

We add all the numbers together, and all the variables

y-7=0

We move all terms containing y to the left, all other terms to the right

y=7

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