3(y-1)=3(y-1)=2(y+2)=(y+11)

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Solution for 3(y-1)=3(y-1)=2(y+2)=(y+11) equation: 



3(y-1)=3(y-1)=2(y+2)=(y+11)

We move all terms to the left:

3(y-1)-(3(y-1))=0

We multiply parentheses

3y-(3(y-1))-3=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We get rid of parentheses

3y-3y+3-3=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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