3(y-1)=4(y+8)-3(y+5)

Solution for 3(y-1)=4(y+8)-3(y+5) equation:

3(y-1)=4(y+8)-3(y+5)

We move all terms to the left:

3(y-1)-(4(y+8)-3(y+5))=0

We multiply parentheses

3y-(4(y+8)-3(y+5))-3=0


We calculate terms in parentheses: -(4(y+8)-3(y+5)), so:

4(y+8)-3(y+5)

We multiply parentheses

4y-3y+32-15

We add all the numbers together, and all the variables

y+17

Back to the equation:

-(y+17)


We get rid of parentheses

3y-y-17-3=0

We add all the numbers together, and all the variables

2y-20=0

We move all terms containing y to the left, all other terms to the right

2y=20

y=20/2

y=10