3(y-1)=4y+3-3(-5y-2)

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Solution for 3(y-1)=4y+3-3(-5y-2) equation: 



3(y-1)=4y+3-3(-5y-2)

We move all terms to the left:

3(y-1)-(4y+3-3(-5y-2))=0

We multiply parentheses

3y-(4y+3-3(-5y-2))-3=0



We calculate terms in parentheses: -(4y+3-3(-5y-2)), so:

4y+3-3(-5y-2)

determiningTheFunctionDomain
4y-3(-5y-2)+3

We multiply parentheses

4y+15y+6+3

We add all the numbers together, and all the variables

19y+9

Back to the equation:

-(19y+9)



We get rid of parentheses

3y-19y-9-3=0

We add all the numbers together, and all the variables

-16y-12=0

We move all terms containing y to the left, all other terms to the right

-16y=12

y=12/-16

y=-3/4

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