3(y-1)=5y+3-2(-7y-1)

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Solution for 3(y-1)=5y+3-2(-7y-1) equation: 



3(y-1)=5y+3-2(-7y-1)

We move all terms to the left:

3(y-1)-(5y+3-2(-7y-1))=0

We multiply parentheses

3y-(5y+3-2(-7y-1))-3=0



We calculate terms in parentheses: -(5y+3-2(-7y-1)), so:

5y+3-2(-7y-1)

determiningTheFunctionDomain
5y-2(-7y-1)+3

We multiply parentheses

5y+14y+2+3

We add all the numbers together, and all the variables

19y+5

Back to the equation:

-(19y+5)



We get rid of parentheses

3y-19y-5-3=0

We add all the numbers together, and all the variables

-16y-8=0

We move all terms containing y to the left, all other terms to the right

-16y=8

y=8/-16

y=-1/2

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