3(y-1)=7y+9-2(-2y-1)

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Solution for 3(y-1)=7y+9-2(-2y-1) equation: 



3(y-1)=7y+9-2(-2y-1)

We move all terms to the left:

3(y-1)-(7y+9-2(-2y-1))=0

We multiply parentheses

3y-(7y+9-2(-2y-1))-3=0



We calculate terms in parentheses: -(7y+9-2(-2y-1)), so:

7y+9-2(-2y-1)

determiningTheFunctionDomain
7y-2(-2y-1)+9

We multiply parentheses

7y+4y+2+9

We add all the numbers together, and all the variables

11y+11

Back to the equation:

-(11y+11)



We get rid of parentheses

3y-11y-11-3=0

We add all the numbers together, and all the variables

-8y-14=0

We move all terms containing y to the left, all other terms to the right

-8y=14

y=14/-8

y=-1+3/4

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