3(y-1)=8y+12

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Solution for 3(y-1)=8y+12 equation: 



3(y-1)=8y+12

We move all terms to the left:

3(y-1)-(8y+12)=0

We multiply parentheses

3y-(8y+12)-3=0

We get rid of parentheses

3y-8y-12-3=0

We add all the numbers together, and all the variables

-5y-15=0

We move all terms containing y to the left, all other terms to the right

-5y=15

y=15/-5

y=-3

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