3(y-1)=y+5-2(-8y-1)

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Solution for 3(y-1)=y+5-2(-8y-1) equation: 



3(y-1)=y+5-2(-8y-1)

We move all terms to the left:

3(y-1)-(y+5-2(-8y-1))=0

We multiply parentheses

3y-(y+5-2(-8y-1))-3=0



We calculate terms in parentheses: -(y+5-2(-8y-1)), so:

y+5-2(-8y-1)

determiningTheFunctionDomain
y-2(-8y-1)+5

We multiply parentheses

y+16y+2+5

We add all the numbers together, and all the variables

17y+7

Back to the equation:

-(17y+7)



We get rid of parentheses

3y-17y-7-3=0

We add all the numbers together, and all the variables

-14y-10=0

We move all terms containing y to the left, all other terms to the right

-14y=10

y=10/-14

y=-5/7

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