3(y-1+)=2(y+3)=13

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Solution for 3(y-1+)=2(y+3)=13 equation: 



3(y-1+)=2(y+3)=13

We move all terms to the left:

3(y-1+)-(2(y+3))=0

We add all the numbers together, and all the variables

3(+y)-(2(y+3))=0

We multiply parentheses

3y-(2(y+3))=0



We calculate terms in parentheses: -(2(y+3)), so:

2(y+3)

We multiply parentheses

2y+6

Back to the equation:

-(2y+6)



We get rid of parentheses

3y-2y-6=0

We add all the numbers together, and all the variables

y-6=0

We move all terms containing y to the left, all other terms to the right

y=6

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