3(y-10)+1=-2(y-16)

Solution for 3(y-10)+1=-2(y-16) equation:

3(y-10)+1=-2(y-16)

We move all terms to the left:

3(y-10)+1-(-2(y-16))=0

We multiply parentheses

3y-(-2(y-16))-30+1=0


We calculate terms in parentheses: -(-2(y-16)), so:

-2(y-16)

We multiply parentheses

-2y+32

Back to the equation:

-(-2y+32)


We add all the numbers together, and all the variables

3y-(-2y+32)-29=0

We get rid of parentheses

3y+2y-32-29=0

We add all the numbers together, and all the variables

5y-61=0

We move all terms containing y to the left, all other terms to the right

5y=61

y=61/5

y=12+1/5