3(y-10)+1=-2y+16

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Solution for 3(y-10)+1=-2y+16 equation: 



3(y-10)+1=-2y+16

We move all terms to the left:

3(y-10)+1-(-2y+16)=0

We multiply parentheses

3y-(-2y+16)-30+1=0

We get rid of parentheses

3y+2y-16-30+1=0

We add all the numbers together, and all the variables

5y-45=0

We move all terms containing y to the left, all other terms to the right

5y=45

y=45/5

y=9

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