3(y-10)+1=2(y-8)

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Solution for 3(y-10)+1=2(y-8) equation:


Simplifying
3(y + -10) + 1 = 2(y + -8)

Reorder the terms:
3(-10 + y) + 1 = 2(y + -8)
(-10 * 3 + y * 3) + 1 = 2(y + -8)
(-30 + 3y) + 1 = 2(y + -8)

Reorder the terms:
-30 + 1 + 3y = 2(y + -8)

Combine like terms: -30 + 1 = -29
-29 + 3y = 2(y + -8)

Reorder the terms:
-29 + 3y = 2(-8 + y)
-29 + 3y = (-8 * 2 + y * 2)
-29 + 3y = (-16 + 2y)

Solving
-29 + 3y = -16 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
-29 + 3y + -2y = -16 + 2y + -2y

Combine like terms: 3y + -2y = 1y
-29 + 1y = -16 + 2y + -2y

Combine like terms: 2y + -2y = 0
-29 + 1y = -16 + 0
-29 + 1y = -16

Add '29' to each side of the equation.
-29 + 29 + 1y = -16 + 29

Combine like terms: -29 + 29 = 0
0 + 1y = -16 + 29
1y = -16 + 29

Combine like terms: -16 + 29 = 13
1y = 13

Divide each side by '1'.
y = 13

Simplifying
y = 13

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