3(y-10)+1=3(y-8)

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Solution for 3(y-10)+1=3(y-8) equation: 


Simplifying
3(y + -10) + 1 = 3(y + -8)

Reorder the terms:
3(-10 + y) + 1 = 3(y + -8)
(-10 * 3 + y * 3) + 1 = 3(y + -8)
(-30 + 3y) + 1 = 3(y + -8)

Reorder the terms:
-30 + 1 + 3y = 3(y + -8)

Combine like terms: -30 + 1 = -29
-29 + 3y = 3(y + -8)

Reorder the terms:
-29 + 3y = 3(-8 + y)
-29 + 3y = (-8 * 3 + y * 3)
-29 + 3y = (-24 + 3y)

Add '-3y' to each side of the equation.
-29 + 3y + -3y = -24 + 3y + -3y

Combine like terms: 3y + -3y = 0
-29 + 0 = -24 + 3y + -3y
-29 = -24 + 3y + -3y

Combine like terms: 3y + -3y = 0
-29 = -24 + 0
-29 = -24

Solving
-29 = -24

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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