3(y-12)=8(y-7)

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Solution for 3(y-12)=8(y-7) equation: 



3(y-12)=8(y-7)

We move all terms to the left:

3(y-12)-(8(y-7))=0

We multiply parentheses

3y-(8(y-7))-36=0



We calculate terms in parentheses: -(8(y-7)), so:

8(y-7)

We multiply parentheses

8y-56

Back to the equation:

-(8y-56)



We get rid of parentheses

3y-8y+56-36=0

We add all the numbers together, and all the variables

-5y+20=0

We move all terms containing y to the left, all other terms to the right

-5y=-20

y=-20/-5

y=+4

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