3(y-2)+1=2(y-3)+(y+1 - solution

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Solution for 3(y-2)+1=2(y-3)+(y+1 equation:


3(y-2)+1=2(y-3)+(y+1

We move all terms to the left:

3(y-2)+1-(2(y-3)+(y+1)=0

We multiply parentheses

3y-(2(y-3)+(y+1)+1-6=0

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