3(y-2)+1=2/3(3y-6)

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Solution for 3(y-2)+1=2/3(3y-6) equation: 



3(y-2)+1=2/3(3y-6)

We move all terms to the left:

3(y-2)+1-(2/3(3y-6))=0



Domain of the equation: 3(3y-6))!=0

y∈R



We multiply parentheses

3y-(2/3(3y-6))-6+1=0

We multiply all the terms by the denominator


3y*3(3y-6))-(2-6*3(3y-6))+1*3(3y-6))=0

We add all the numbers together, and all the variables

3y*3(3y-6))-(2-6*3(3y-6))+1*3(3y=0

Wy multiply elements

9y^2(3-54y^2(3=0

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