3(y-2)+2(y+1)=-14

Solution for 3(y-2)+2(y+1)=-14 equation:

Simplifying
3(y + -2) + 2(y + 1) = -14

Reorder the terms:
3(-2 + y) + 2(y + 1) = -14
(-2 * 3 + y * 3) + 2(y + 1) = -14
(-6 + 3y) + 2(y + 1) = -14

Reorder the terms:
-6 + 3y + 2(1 + y) = -14
-6 + 3y + (1 * 2 + y * 2) = -14
-6 + 3y + (2 + 2y) = -14

Reorder the terms:
-6 + 2 + 3y + 2y = -14

Combine like terms: -6 + 2 = -4
-4 + 3y + 2y = -14

Combine like terms: 3y + 2y = 5y
-4 + 5y = -14

Solving
-4 + 5y = -14

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 5y = -14 + 4

Combine like terms: -4 + 4 = 0
0 + 5y = -14 + 4
5y = -14 + 4

Combine like terms: -14 + 4 = -10
5y = -10

Divide each side by '5'.
y = -2

Simplifying
y = -2